Exercise Solution 5.3

Exercise Solution 5.3

  1. The integral is solved analytically as


  2. Given change of variables


    the inverse is


    so the new bounds of integration are g–1(1) = 1 and g–1(–1) = 0. By [2.166], change of variables [s2] converts integral [5.40] to


c,d. See spreadsheet for solutions to parts (c) and (d).

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