Exercise Solution 5.3
- The integral is solved analytically as
[s1]
- Given change of variables
[s2]
the inverse is
[s3]
so the new bounds of integration are g–1(1) = 1 and g–1(–1) = 0. By [2.166], change of variables [s2] converts integral [5.40] to
[s4]
c,d. See spreadsheet for solutions to parts (c) and (d).