Exercise Solution 3.36

Exercise Solution 3.36

Random variable X has mean μ = 1.1 and standard deviation σ = .25. By [3.105] and [3.106], we calculate m = .070 and s = .224. Accordingly, X = exp(.224Z + .070), where Z ~ N(0,1). Denote the CDFs of X and Z as ΦX and ΦZ. Then

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