# Exercise Solution 3.34

Let *Z* ~ *N*(0,1) such that:

[s1]

[s2]

From a standard normal table, the .15-quantile of *Z* is –1.04, so

[s3]

[s4]

[s5]

Accordingly, the .15-quantile Φ^{−1}(.15) of *X* is 93.76.

Let *Z* ~ *N*(0,1) such that:

[s1]

[s2]

From a standard normal table, the .15-quantile of *Z* is –1.04, so

[s3]

[s4]

[s5]

Accordingly, the .15-quantile Φ^{−1}(.15) of *X* is 93.76.