# Exercise Solution 2.4

Let

*f*_{1}(*x*) = 1*f*_{2}(*x*) =*x**f*_{3}(*x*) =*x*^{2}

Then

[s1]

and

[s2]

We seek

[s3]

such that

[2.48]

This is obtained as

[s4]

Our interpolated polynomial is

[s5]

Let

*f*_{1}(*x*) = 1*f*_{2}(*x*) =*x**f*_{3}(*x*) =*x*^{2}

Then

[s1]

and

[s2]

We seek

[s3]

such that

[2.48]

This is obtained as

[s4]

Our interpolated polynomial is

[s5]