Exercise Solution 2.2

Formula [2.26] provides a quadratic polynomial approximation p2(x) for the function f(x):

[2.26]

We have

[s1]

and

[s2]

Valuing f, f, and 2f at x[0] = (0, 0), we obtain

[s3]

[s4]

[s5]

Substituting these into [2.26], our result is

[s6]

[s7]

 

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